Light and Geometric Optics光与几何光学
Light is the centrepiece of optics: an electromagnetic wave that also behaves as a stream of photons. This guide covers the full geometric-optics strand, starting with the electromagnetic spectrum and the dual nature of light, then building through the law of reflection (plane and curved mirrors), Snell's law of refraction, total internal reflection and fibre optics, the thin-lens equation and ray diagrams, and finally the compound optical instruments (cameras, microscopes, telescopes) that depend on these principles. Every section includes worked examples with real numbers and interactive quizzes. Ontario SPH3U/SPH4U is the strongest curriculum anchor; NGSS treats optics conceptually under HS-PS4, BC Physics 11 covers wave behaviours including refraction, and Alberta Physics 30 Unit C gives quantitative geometric optics within its electromagnetic radiation strand.光(light,光)是光学的核心:它既是电磁波(electromagnetic wave,电磁波),也表现为光子流。本指南涵盖完整的几何光学脉络:从电磁波谱(electromagnetic spectrum,电磁波谱)与光的波粒二象性出发,逐步建立反射定律(平面镜与曲面镜)、斯涅尔折射定律(Snell's law,斯涅尔定律)、全内反射(total internal reflection,全内反射)与光纤、薄透镜方程(thin-lens equation,薄透镜方程)及光路图,最后讲解依赖上述原理的复合光学仪器(相机、显微镜、望远镜)。每节均含有真实数字的例题与交互测验。安大略 SPH3U/SPH4U 是最强的大纲锚点;NGSS 在 HS-PS4 下从概念层面处理光学;BC Physics 11 涵盖包括折射在内的波动行为;阿尔伯塔 Physics 30 C 单元在电磁辐射框架内给出定量几何光学。
How to use this guide如何使用本指南
Light and Geometric Optics is a full curriculum strand in Ontario SPH3U and appears quantitatively in Alberta Physics 30 Unit C. NGSS treats the subject conceptually (no ray-diagram or mirror/lens equation PE); BC Physics 11 covers wave behaviours (reflection, refraction) but has no dedicated geometric-optics content strand. The table tells you which sections are core for your curriculum right now.光与几何光学是安大略 SPH3U 的完整课程单元,也在阿尔伯塔 Physics 30 C 单元中以定量形式出现。NGSS 仅从概念层面处理此主题(无光路图或镜-透镜方程 PE);BC Physics 11 涵盖波动行为(反射、折射),但无专项几何光学内容单元。下表告诉你当前哪些节是你的核心学习内容。
| If you are in…如果你在… | Focus on these sections重点学习 | Defer / lighter可推迟 / 减负 | Source依据 |
|---|---|---|---|
| 🇺🇸 US NGSS HS Physical Science美国 NGSS 物理科学 | §1 (wave-particle nature of light, EM spectrum — HS-PS4-3); §7 conceptually (optical devices — HS-PS4-5)§1(光的波粒性质、电磁波谱 — HS-PS4-3);§7 概念层面(光学装置 — HS-PS4-5) | §3, §6 (mirror/lens equations): NGSS has no standalone geometric-optics PE; these sections are beyond the assessed NGSS core§3、§6(镜方程/透镜方程):NGSS 无独立几何光学 PE;这些节超出 NGSS 被评估的核心 | ngss_hs_ps_extract.md — HS-PS4-3, HS-PS4-5— HS-PS4-3、HS-PS4-5 |
| 🇨🇦 ON Grade 11 — SPH3U安大略 11 年级 — SPH3U | §1 through §7 in full. Light and Geometric Optics is a complete SPH3U strand with reflection, refraction, TIR, lenses, and optical instruments all assessed§1 至 §7 完整学习。光与几何光学是 SPH3U 的完整单元,反射、折射、全内反射、透镜与光学仪器均被评估 | Nothing — the full unit is on the Grade 11 syllabus无 — 全单元都在 11 年级大纲内 | science_11-12_physics_extract.md — SPH3U Light & Geometric Optics strand (Overall Expectations)— SPH3U 光与几何光学单元(总体期望) |
| 🇨🇦 BC Grade 11 — Physics 11BC 11 年级 — Physics 11 | §1, §2, §4, §5 (EM spectrum, reflection, refraction, TIR — covered as wave behaviours)§1、§2、§4、§5(电磁波谱、反射、折射、全内反射 — 作为波动行为涵盖) | §3, §6, §7 (mirror equations, lens equations, compound instruments): no dedicated ray-optics content strand in BC Physics 11 or 12§3、§6、§7(镜方程、透镜方程、复合仪器):BC Physics 11 或 12 均无专项光线光学内容单元 | physics_11-12_extract.md — Physics 11 Content: "properties and behaviours of waves" (reflection, refraction, diffraction)— Physics 11 内容:"波的性质与行为"(反射、折射、衍射) |
| 🇨🇦 AB Grade 12 — Physics 30阿尔伯塔 12 年级 — Physics 30 | §1 through §6 in full (Physics 30 Unit C GO1 outcomes 30–C1.2k through 30–C1.7k cover EM spectrum, reflection, refraction, TIR, mirrors, lenses quantitatively); §7 conceptually§1 至 §6 完整学习(Physics 30 C 单元 GO1 outcomes 30–C1.2k 至 30–C1.7k 定量涵盖电磁波谱、反射、折射、全内反射、曲面镜、透镜);§7 概念层面 | Physics 20 students: this entire unit is enrichment only — optics first appears in Physics 30Physics 20 学生:本单元全属拓展 — 光学首见于 Physics 30 | physics_20-30_extract.md — Physics 30 Unit C GO1 knowledge outcomes 30–C1.2k through 30–C1.7k— Physics 30 C 单元 GO1 知识 outcomes 30–C1.2k 至 30–C1.7k |
Once you have located your row, use the two cards below for the pace at which you should work through the recommended sections.找到所在行后,用下面两张卡片决定推进速度。
Memorise four things: Snell's law $n_1\sin\theta_1 = n_2\sin\theta_2$; the thin-lens/mirror equation $\tfrac{1}{f} = \tfrac{1}{d_o} + \tfrac{1}{d_i}$; the critical-angle formula $\sin\theta_c = n_2/n_1$; and that real images from converging lenses are inverted while virtual images are upright. Read every cram-cheat box. Skip the going-deeper derivations.背熟四件事:斯涅尔定律 $n_1\sin\theta_1 = n_2\sin\theta_2$;薄透镜/镜方程 $\tfrac{1}{f} = \tfrac{1}{d_o} + \tfrac{1}{d_i}$;临界角公式 $\sin\theta_c = n_2/n_1$;以及会聚透镜产生的实像是倒立的,虚像是正立的。读每个速记框,跳过深入推导。
Always draw a ray diagram before applying any formula; the diagram reveals sign conventions and whether an image is real or virtual. For lenses and mirrors, adopt the real-is-positive sign convention from the start. Practise tracing the three principal rays for both converging and diverging cases. For TIR problems, check that light travels from the denser to the less-dense medium before applying the critical-angle formula. Ontario SPH3U and Alberta Physics 30 both expect quantitative solutions with full significant-figure discipline.写任何公式前先画光路图;图能揭示符号约定并判断像是实像还是虚像。对透镜与曲面镜,从一开始就采用实-为-正的符号约定。反复练习对会聚和发散情形各追踪三条主光线。做全内反射题前先确认光从光密介质射向光疏介质,再套临界角公式。安大略 SPH3U 和阿尔伯塔 Physics 30 都要求定量解题并严格保留有效数字。
Nature of Light and the Electromagnetic Spectrum光(光)的本质与电磁波谱(电磁波谱)
- Wave model波动模型 — light travels as perpendicular electric and magnetic fields oscillating at right angles to the direction of propagation. Speed in vacuum $c = 3.00 \times 10^8\ \mathrm{m/s}$; $c = f\lambda$.— 光以垂直于传播方向的电场与磁场相互振荡的方式传播。真空中速度 $c = 3.00 \times 10^8\ \mathrm{m/s}$;$c = f\lambda$。
- Particle (photon) model粒子(光子)模型 — light carries energy in discrete quanta. Photon energy $E = hf$, where $h = 6.63 \times 10^{-34}\ \mathrm{J\cdot s}$ (Planck's constant). Higher frequency = more energetic photons.— 光以离散量子携带能量。光子能量 $E = hf$,其中 $h = 6.63 \times 10^{-34}\ \mathrm{J\cdot s}$(普朗克常量)。频率越高,光子能量越大。
- EM spectrum order电磁波谱顺序 (increasing frequency / decreasing wavelength): radio → microwave → infrared → visible → UV → X-ray → gamma. Visible light spans roughly $400$–$700$ nm.(频率递增 / 波长递减):无线电 → 微波 → 红外 → 可见光 → 紫外 → X 射线 → 伽马射线。可见光约为 $400$–$700$ nm。
HS-PS4-3: "evaluate claims behind the idea that EMR can be described by a wave model or a particle model, and that for some situations one model is more useful than the other." This is the conceptual core of §1.NGSS HS-PS4-3:"评估 EMR 可用波动模型或粒子模型描述、且各情境下各有优势这一观点的论据。"这是 §1 的概念核心。
Green light has a wavelength of $520$ nm in vacuum. Find (a) its frequency and (b) the energy of one photon. Use $c = 3.00 \times 10^8\ \mathrm{m/s}$ and $h = 6.63 \times 10^{-34}\ \mathrm{J\cdot s}$.绿光在真空中的波长为 $520$ nm。求 (a) 其频率与 (b) 一个光子的能量。取 $c = 3.00 \times 10^8\ \mathrm{m/s}$,$h = 6.63 \times 10^{-34}\ \mathrm{J\cdot s}$。
(a) Frequency from wave speed.(a) 由波速求频率。 Convert nm to m: $520\ \mathrm{nm} = 520 \times 10^{-9}\ \mathrm{m}$.把 nm 换算为 m:$520\ \mathrm{nm} = 520 \times 10^{-9}\ \mathrm{m}$。
$$ f = \frac{c}{\lambda} = \frac{3.00 \times 10^8}{520 \times 10^{-9}} \approx 5.77 \times 10^{14}\ \mathrm{Hz}. $$(b) Photon energy.(b) 光子能量。
$$ E = hf = (6.63 \times 10^{-34})(5.77 \times 10^{14}) \approx 3.83 \times 10^{-19}\ \mathrm{J}. $$Interpretation.解读。 A single green photon carries about $3.8 \times 10^{-19}$ J — tiny, but billions of photons per second reach your eye from a lamp. The wave model predicts the frequency; the photon model predicts the energy per quantum.一个绿色光子携带约 $3.8 \times 10^{-19}$ J — 极小,但灯每秒向眼睛发送数十亿光子。波动模型预测频率;光子模型预测每个量子的能量。
Going deeper — wave-particle duality and when each model applies (NGSS HS-PS4-3)深入 — 波粒二象性与各模型的适用情境(NGSS HS-PS4-3)
The wave model predicts diffraction, interference, and refraction — phenomena that require a spread-out oscillation to explain why light bends around corners, produces coloured fringes, and slows in dense media. The particle model is essential for the photoelectric effect (a single photon either ejects an electron or it does not; intensity doesn't matter, only frequency does) and for explaining why high-frequency radiation damages tissue more per quantum than low-frequency radiation.波动模型预测衍射、干涉与折射 — 这些现象需要弥散振荡来解释光绕角弯曲、产生彩色条纹、以及在致密介质中减速的原因。粒子模型对光电效应不可或缺(单个光子要么打出电子要么打不出;强度无关紧要,只有频率决定结果),也能解释为何高频辐射每个量子对组织的损伤比低频辐射更大。
Modern quantum mechanics unifies both views: light is described by a quantum field, and the wave-like or particle-like behaviour you observe depends on how you set up the experiment. For HS optics, the rule of thumb is: use the wave model for refraction, reflection, and diffraction (§1–§5 of this guide); use the photon model when energy transfer per quantum matters (photoelectric effect, photon energy questions).现代量子力学统一了两种观点:光由量子场描述,观测到的波动或粒子行为取决于实验的设置方式。在高中光学中,经验法则是:折射、反射与衍射用波动模型(本指南 §1–§5);每个量子的能量转移有意义时(光电效应、光子能量问题)用光子模型。
Reflection and Plane Mirrors反射与平面镜
- Normal法线 — a line perpendicular to the mirror surface at the point of incidence. All angles are measured from the normal, not from the mirror surface.— 在入射点垂直于镜面的直线。所有角度均从法线量起,而非从镜面量起。
- Specular vs diffuse reflection.镜面反射与漫反射。 A flat, polished surface gives specular (mirror-like) reflection where all rays obey the same angle. A rough surface scatters light in many directions (diffuse reflection).光滑平整的表面产生镜面反射,所有光线遵循相同角度。粗糙表面使光向多方向散射(漫反射)。
- Plane mirror image properties平面镜成像特性 — (i) virtual (behind the mirror), (ii) upright, (iii) same size as the object, (iv) image distance $= $ object distance.— (i) 虚像(在镜后),(ii) 正立,(iii) 与物等大,(iv) 像距 $=$ 物距。
30–C1.6k requires students to "describe, quantitatively, the phenomena of reflection and refraction." Plane-mirror geometry is the entry point for all curved-mirror and lens work in §3 and §6.阿尔伯塔 30–C1.6k 要求学生"定量描述反射与折射现象"。平面镜几何是 §3 与 §6 中曲面镜和透镜内容的起点。
An object stands $0.35$ m in front of a large flat mirror. (a) Where is the image? (b) Is the image real or virtual? (c) If the object is $0.20$ m tall, how tall is the image?一个物体立于大型平面镜前 $0.35$ m 处。(a) 像在哪里?(b) 像是实像还是虚像?(c) 若物体高 $0.20$ m,像高多少?
(a) Image distance.(a) 像距。 For a plane mirror, $d_i = d_o$, so the image is $0.35$ m behind the mirror.平面镜中 $d_i = d_o$,故像在镜后 $0.35$ m 处。
(b) Real or virtual?(b) 实像还是虚像? The image is virtual: light rays do not actually converge behind the mirror; they only appear to diverge from that point when observed from the front.像是虚像:光线并不真正会聚于镜后;从正面观察时,光线仅看起来从那一点发散。
(c) Image height.(c) 像高。 A plane mirror produces magnification $m = 1$, so the image is the same height: $0.20$ m, upright.平面镜放大率 $m = 1$,故像与物等高:$0.20$ m,正立。
Going deeper — why a plane mirror reverses left-right but not up-down深入 — 平面镜为何左右互换而上下不翻转
The mirror does not actually swap left and right in space — it swaps front and back (depth). If you face north and look in a mirror, the reflection appears to face south. The "left-right reversal" you perceive is a cognitive effect: you mentally rotate the image around a vertical axis to face it, and that rotation swaps left and right. If you instead imagine rotating the image over a horizontal axis, it would look upside down with left and right unchanged. The mirror itself only reverses the dimension perpendicular to its surface.镜子并未真正在空间上交换左右,它交换的是前后(深度)。若你面朝北看镜子,映像看起来面朝南。你感知到的"左右互换"是认知效应:你在心理上将映像绕竖直轴旋转来面对它,而这个旋转就使左右互换了。若改为绕水平轴旋转映像,它看起来是上下颠倒但左右不变的。镜子本身只是反转了垂直于其镜面的那个维度。
Curved Mirrors: Concave and Convex曲面镜:凹镜与凸镜
- Sign convention (real-positive).符号约定(实-为-正)。 Object distance $d_o > 0$ always. Real image: $d_i > 0$ (same side as the object). Virtual image: $d_i < 0$ (behind the mirror). Focal length: concave mirror $f > 0$; convex $f < 0$.物距 $d_o > 0$ 恒成立。实像:$d_i > 0$(与物同侧)。虚像:$d_i < 0$(在镜后)。焦距:凹镜 $f > 0$;凸镜 $f < 0$。
- Concave (converging) mirror凹(会聚)镜 — parallel rays converge at the focal point $F$, at distance $f = R/2$ from the mirror. Used in car headlights, telescopes, dental mirrors. Can form real or virtual images depending on object position.— 平行光线会聚于焦点 $F$,焦距 $f = R/2$。用于车头灯、望远镜、牙科镜。根据物体位置可形成实像或虚像。
- Convex (diverging) mirror凸(发散)镜 — always forms a virtual, upright, diminished image. Used in car wing mirrors and security mirrors for wide-angle coverage.— 总形成虚像、正立、缩小的像。用于汽车后视镜和安全监控镜,提供广角视野。
30–C1.7k: "describe, quantitatively, simple optical systems, consisting of only one component, for both lenses and curved mirrors" — this section satisfies the curved-mirror half.阿尔伯塔 30–C1.7k:"定量描述仅含一个元件(透镜或曲面镜)的简单光学系统"——本节满足曲面镜部分。
A concave mirror has a focal length of $12$ cm. An object is placed $30$ cm in front of the mirror. Find (a) the image distance and (b) the magnification.一块凹镜焦距为 $12$ cm,物体置于镜前 $30$ cm 处。求 (a) 像距与 (b) 放大率。
(a) Image distance via mirror equation.(a) 由镜方程求像距。 $f = +12$ cm (concave), $d_o = +30$ cm.$f = +12$ cm(凹镜),$d_o = +30$ cm。
$$ \frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o} = \frac{1}{12} - \frac{1}{30} = \frac{5}{60} - \frac{2}{60} = \frac{3}{60} = \frac{1}{20}. $$ $$ d_i = +20\ \text{cm} \quad \Rightarrow \quad \text{real image, in front of the mirror.} $$(b) Magnification.(b) 放大率。
$$ m = -\frac{d_i}{d_o} = -\frac{20}{30} = -0.67. $$Interpret.解读。 The negative sign means the image is inverted. Magnitude $0.67 < 1$ means the image is smaller than the object. The image is real (positive $d_i$), inverted, and diminished.负号表示像是倒立的。大小 $0.67 < 1$ 表示像比物小。像是实像($d_i > 0$)、倒立、缩小。
Going deeper — the three principal rays for curved mirrors深入 — 曲面镜的三条主光线
Any two of these three rays locate the image graphically for a concave mirror (reverse the focal-point directions for a convex mirror):以下三条光线中任意两条可以图解法确定凹镜的像(凸镜则将焦点方向反转):
- A ray parallel to the principal axis reflects through the focal point $F$.平行于主轴的光线经反射后过焦点 $F$。
- A ray through the focal point $F$ reflects parallel to the principal axis.过焦点 $F$ 的光线经反射后平行于主轴。
- A ray directed at the centre of curvature $C$ reflects back along itself (it hits the mirror perpendicularly).指向曲率中心 $C$ 的光线沿原路反射回来(它垂直射到镜面)。
For a concave mirror with the object beyond $C$: image is real, inverted, diminished. Between $F$ and $C$: real, inverted, magnified. Inside $F$: virtual, upright, magnified (magnifying glass geometry). At $F$: no image (reflected rays are parallel). These cases are all predictable from the mirror equation; the ray diagram confirms the sign of $d_i$.物体在曲率中心 $C$ 之外时:实像、倒立、缩小。在 $F$ 与 $C$ 之间时:实像、倒立、放大。在 $F$ 之内时:虚像、正立、放大(放大镜几何)。在 $F$ 处:无像(反射光线平行)。这些情形均可由镜方程预测;光路图确认 $d_i$ 的符号。
Refraction and Snell's Law折射与斯涅尔定律
- Index of refraction $n$折射率 $n$ — ratio of the speed of light in vacuum to its speed in the medium: $n = c/v$. $n \ge 1$ always ($n_{\text{vacuum}} = 1$, $n_{\text{water}} \approx 1.33$, $n_{\text{glass}} \approx 1.5$).— 光在真空中的速度与在该介质中速度之比:$n = c/v$。恒有 $n \ge 1$($n_{\text{真空}} = 1$,$n_{\text{水}} \approx 1.33$,$n_{\text{玻璃}} \approx 1.5$)。
- Bending direction.弯折方向。 When light enters a denser medium ($n_2 > n_1$), it bends toward the normal ($\theta_2 < \theta_1$). Into a less dense medium: bends away from the normal.光进入光密介质($n_2 > n_1$)时,弯向法线($\theta_2 < \theta_1$)。进入光疏介质时,偏离法线。
- All angles from the normal.所有角度均从法线量起。 Subscript 1 = incident side; subscript 2 = transmitted side. Measure $\theta_1$ and $\theta_2$ from the normal at the point of incidence.下标 1 = 入射侧;下标 2 = 透射侧。在入射点从法线量 $\theta_1$ 与 $\theta_2$。
30–C1.11k (verbatim from extract): "describe, qualitatively and quantitatively, how refraction supports the wave model of EMR" using $\sin\theta_1/\sin\theta_2 = n_2/n_1$. BC Physics 11 names refraction as a wave behaviour in its Content strand.阿尔伯塔 30–C1.11k(原文):"定性与定量地描述折射如何支持 EMR 的波动模型",使用 $\sin\theta_1/\sin\theta_2 = n_2/n_1$。BC Physics 11 在内容单元中把折射列为波动行为。
A ray of light travels in air ($n_1 = 1.00$) and strikes the flat surface of a glass block ($n_2 = 1.52$) at an angle of incidence of $40.0^{\circ}$. Find the angle of refraction inside the glass.一束光在空气($n_1 = 1.00$)中传播,以 $40.0^{\circ}$ 的入射角射到玻璃块($n_2 = 1.52$)的平面上。求光在玻璃内的折射角。
Apply Snell's law.应用斯涅尔定律。
$$ n_1\sin\theta_1 = n_2\sin\theta_2 \;\Longrightarrow\; \sin\theta_2 = \frac{n_1\sin\theta_1}{n_2} = \frac{1.00 \times \sin 40.0^{\circ}}{1.52}. $$ $$ \sin\theta_2 = \frac{1.00 \times 0.643}{1.52} = 0.423 \;\Longrightarrow\; \theta_2 = \arcsin(0.423) \approx 25.0^{\circ}. $$Interpret.解读。 The ray bends toward the normal on entering the denser glass ($25.0^{\circ} < 40.0^{\circ}$). If the ray exits back into air, Snell's law reverses and $\theta$ returns to $40.0^{\circ}$ (the emerging ray is parallel to the incident ray for a parallel-sided block).光进入光密玻璃时偏向法线($25.0^{\circ} < 40.0^{\circ}$)。若光射回空气,斯涅尔定律反向,$\theta$ 恢复为 $40.0^{\circ}$(平行侧面的玻璃块中,出射光线与入射光线平行)。
Going deeper — why light slows down in a dense medium (wave model explanation)深入 — 光在光密介质中为何减速(波动模型解释)
In vacuum, the electromagnetic wave oscillates in free space at speed $c$. In a material, the oscillating electric field drives the bound electrons in atoms to oscillate, which re-emit the wave with a slight phase lag. The net effect of the superposition of the original wave and the re-emitted waves is a wave that travels at a lower phase velocity $v = c/n$. The frequency is unchanged (it is set by the source); only the wavelength shrinks: $\lambda_{\text{medium}} = \lambda_{\text{vacuum}}/n$. This is why a denser glass bends light more: its higher $n$ means a greater speed difference and a larger change in direction via Snell's law. Chromatic dispersion (the splitting of white light into colours by a prism) occurs because $n$ is slightly different for each wavelength, so each colour bends by a slightly different amount.在真空中,电磁波以速度 $c$ 在自由空间中振荡。在介质中,振荡的电场驱动原子中的束缚电子振荡,并以轻微的相位滞后重新辐射波。原波与重辐射波的叠加净效果是一列以较低相速度 $v = c/n$ 传播的波。频率不变(由光源决定);只有波长缩短:$\lambda_{\text{介质}} = \lambda_{\text{真空}}/n$。这就是为何光密玻璃弯折光的程度更大:其较高的 $n$ 意味着更大的速度差,通过斯涅尔定律产生更大的方向改变。色散(棱镜将白光分解为颜色)的发生是因为 $n$ 对每种波长略有不同,故每种颜色弯折量略有差异。
Total Internal Reflection and Fibre Optics全内反射与光纤
- Critical angle $\theta_c$临界角 $\theta_c$ — the angle of incidence (from the normal) at which the refracted ray grazes the boundary ($\theta_2 = 90^{\circ}$). For $\theta_1 > \theta_c$, no refracted ray exists; all light is reflected back into the dense medium.— 折射光线沿界面掠行($\theta_2 = 90^{\circ}$)时的入射角(从法线量)。当 $\theta_1 > \theta_c$ 时,不存在折射光线;所有光线被反射回光密介质。
- Conditions for TIR全内反射(全内反射)的条件 — (i) light must travel from a denser medium to a less dense medium ($n_1 > n_2$); (ii) the angle of incidence must exceed $\theta_c$.— (i) 光必须从光密介质射向光疏介质($n_1 > n_2$);(ii) 入射角必须超过 $\theta_c$。
- Optical fibre光纤 — a glass or plastic core with $n_{\text{core}} > n_{\text{cladding}}$. Light bounces along by successive TIR, carrying data as pulses with very low loss over long distances. NGSS
HS-PS4-5gives fibre-optic communications as an example of "wave interactions with matter to transmit information."— 玻璃或塑料芯,$n_{\text{芯}} > n_{\text{包层}}$。光通过连续全内反射沿纤维传播,以脉冲形式在长距离内传输数据且损耗极低。NGSSHS-PS4-5把光纤通信列为"波与物质相互作用传输信息"的例子。
A glass block has $n = 1.50$. Find the critical angle for the glass-air interface.一块玻璃折射率 $n = 1.50$,求玻璃-空气界面的临界角。
Apply the critical-angle formula.套用临界角公式。 $n_1 = 1.50$ (glass), $n_2 = 1.00$ (air).$n_1 = 1.50$(玻璃),$n_2 = 1.00$(空气)。
$$ \sin\theta_c = \frac{n_2}{n_1} = \frac{1.00}{1.50} = 0.667 \;\Longrightarrow\; \theta_c = \arcsin(0.667) \approx 41.8^{\circ}. $$Interpret.解读。 Any ray inside the glass hitting the glass-air boundary at more than $41.8^{\circ}$ from the normal undergoes total internal reflection and stays in the glass. This is exactly the principle that confines light inside an optical fibre — the core has $\theta_c \approx 40^{\circ}$–$50^{\circ}$ depending on the glass composition.玻璃内任何以超过 $41.8^{\circ}$(从法线量)射到玻璃-空气界面的光线都会发生全内反射并留在玻璃内。这正是将光限制在光纤内的原理 — 纤芯的 $\theta_c$ 约为 $40^{\circ}$–$50^{\circ}$,取决于玻璃成分。
Going deeper — step-index vs graded-index optical fibres深入 — 阶跃折射率光纤与渐变折射率光纤
A step-index fibre has a uniform-$n$ core surrounded by a lower-$n$ cladding. Light entering within the acceptance cone bounces down the fibre by TIR. The problem: different ray angles travel different path lengths, arriving at slightly different times — called modal dispersion — which limits the bandwidth of the cable.
A graded-index fibre has a core whose refractive index decreases smoothly from the centre outward. Rays that venture farther from the axis travel through lower-$n$ regions where they move faster, compensating for the longer path. All rays arrive at nearly the same time, dramatically increasing bandwidth. Graded-index multimode fibres are used in campus and data-centre networks; single-mode fibres (very thin core) eliminate modal dispersion entirely and are used for long-haul telecommunications.阶跃折射率光纤具有均匀折射率芯,外包较低折射率的包层。在接受锥内射入的光通过全内反射沿光纤传播。问题在于:不同角度的光线经过不同路径长度,到达时间略有不同 — 称为模式色散 — 限制了电缆带宽。
渐变折射率光纤的芯部折射率从中心向外平滑降低。偏离轴线较远的光线穿过折射率较低的区域,在那里速度较快,补偿了较长的路径。所有光线几乎同时到达,大幅提高带宽。渐变折射率多模光纤用于校园和数据中心网络;单模光纤(芯极细)完全消除模式色散,用于长途电信。
Lenses: Converging and Diverging透镜:会聚透镜与发散透镜
- Converging (convex) lens会聚(凸)透镜 — $f > 0$. Parallel rays converge to the focal point on the far side. Forms real, inverted images when the object is beyond $f$; virtual, upright, enlarged when inside $f$ (magnifying glass).— $f > 0$。平行光线会聚于远侧焦点。物在 $f$ 外时形成实像、倒立;物在 $f$ 内时形成虚像、正立、放大(放大镜)。
- Diverging (concave) lens发散(凹)透镜 — $f < 0$. Always produces a virtual, upright, diminished image on the same side as the object. Used in spectacles for short-sightedness.— $f < 0$。总在物侧形成虚像、正立、缩小。用于近视矫正眼镜。
- Sign convention.符号约定。 $d_o > 0$ always. $d_i > 0$ for real images (far side of lens); $d_i < 0$ for virtual images (same side as object). Positive $m$: upright; negative $m$: inverted. $|m| > 1$: magnified; $|m| < 1$: diminished.$d_o > 0$ 恒成立。$d_i > 0$ 为实像(透镜远侧);$d_i < 0$ 为虚像(与物同侧)。$m$ 为正:正立;$m$ 为负:倒立。$|m| > 1$:放大;$|m| < 1$:缩小。
30–C1.7k: "describe, quantitatively, simple optical systems, consisting of only one component, for both lenses and curved mirrors." Ontario SPH3U covers lenses as a full expectation within the Light strand.阿尔伯塔 30–C1.7k:"定量描述仅含一个元件(透镜或曲面镜)的简单光学系统。"安大略 SPH3U 在光学单元内把透镜作为完整期望内容。
A converging lens has a focal length of $15.0$ cm. An object is placed $40.0$ cm from the lens. Find (a) the image distance and (b) the magnification. State whether the image is real or virtual, upright or inverted.一块会聚透镜焦距为 $15.0$ cm,物体距透镜 $40.0$ cm。求 (a) 像距与 (b) 放大率。说明像是实像还是虚像、正立还是倒立。
(a) Thin-lens equation.(a) 薄透镜方程。 $f = +15.0$ cm, $d_o = +40.0$ cm.$f = +15.0$ cm,$d_o = +40.0$ cm。
$$ \frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o} = \frac{1}{15.0} - \frac{1}{40.0} = \frac{8}{120} - \frac{3}{120} = \frac{5}{120} = \frac{1}{24.0}. $$ $$ d_i = +24.0\ \text{cm} \quad \Rightarrow \quad \text{real image, on the far side of the lens.} $$(b) Magnification.(b) 放大率。
$$ m = -\frac{d_i}{d_o} = -\frac{24.0}{40.0} = -0.60. $$Summary.总结。 The image is real ($d_i > 0$), inverted ($m < 0$), and diminished ($|m| = 0.60 < 1$). In practice this is a projector geometry: the object (slide or film) is beyond $f$, forming a real, inverted, enlarged image on a screen when $d_o$ is only slightly beyond $f$.像是实像($d_i > 0$)、倒立($m < 0$)、缩小($|m| = 0.60 < 1$)。实际上这是投影仪几何:物体(幻灯片或胶片)在 $f$ 之外,当 $d_o$ 仅略大于 $f$ 时,在屏幕上形成实像、倒立、放大的像。
Going deeper — power of a lens and the lensmaker's equation深入 — 透镜的光焦度与磨镜者方程
Optometrists specify lenses in dioptres (D), where power $P = 1/f$ with $f$ in metres. A converging lens of $f = 0.25$ m has $P = +4.0$ D; a diverging lens of $f = -0.5$ m has $P = -2.0$ D. When two thin lenses are in contact, their powers add: $P_{\text{total}} = P_1 + P_2$. This is why a pair of spectacle lenses is characterised by a single dioptre value.验光师以屈光度(D)标注透镜,其中光焦度 $P = 1/f$($f$ 以米计)。$f = 0.25$ m 的会聚透镜光焦度为 $+4.0$ D;$f = -0.5$ m 的发散透镜为 $-2.0$ D。两块薄透镜紧贴时,光焦度相加:$P_{\text{总}} = P_1 + P_2$。这就是为何一副眼镜用单一屈光度值描述。
The lensmaker's equation relates focal length to the lens geometry and material: $\tfrac{1}{f} = (n-1)\!\left(\tfrac{1}{R_1} - \tfrac{1}{R_2}\right)$, where $n$ is the refractive index of the glass and $R_1$, $R_2$ are the signed radii of curvature of the two surfaces. This equation shows why a lens made of higher-$n$ glass (or with more curved surfaces) has a shorter focal length and greater bending power.磨镜者方程将焦距与透镜几何形状及材料相联系:$\tfrac{1}{f} = (n-1)\!\left(\tfrac{1}{R_1} - \tfrac{1}{R_2}\right)$,其中 $n$ 是玻璃折射率,$R_1$、$R_2$ 是两个面的带符号曲率半径。该方程说明为何由折射率较高的玻璃(或曲率更大的面)制成的透镜焦距更短、弯折能力更强。
Optical Instruments and the Eye光学仪器与眼睛
- The eye眼睛 — the cornea and the adjustable crystalline lens together form a real, inverted image on the retina. The ciliary muscles change the lens curvature (accommodation) to focus near or far objects. Short-sightedness (myopia): eyeball too long → image forms in front of retina → corrected with a diverging lens ($f < 0$). Long-sightedness (hyperopia): eyeball too short → corrected with a converging lens ($f > 0$).— 角膜与可调节的晶状体共同在视网膜上形成实像、倒立的像。睫状肌改变晶状体曲率(调节)以聚焦近处或远处物体。近视:眼轴过长 → 像成于视网膜前方 → 用发散透镜($f < 0$)矫正。远视:眼轴过短 → 用会聚透镜($f > 0$)矫正。
- Simple microscope (magnifying glass)简单显微镜(放大镜) — one converging lens, object inside $f$. Angular magnification $M \approx D/f$, where $D = 25$ cm is the standard near-point distance.— 单块会聚透镜,物在 $f$ 内。角放大率 $M \approx D/f$,其中 $D = 25$ cm 为标准近点距离。
- Compound microscope复合显微镜 — objective lens (short $f_o$, forms a real, magnified intermediate image) + eyepiece (acts as a magnifying glass). Total magnification $M = m_o \times M_e$.— 物镜(短 $f_o$,形成实像、放大的中间像)+ 目镜(充当放大镜)。总放大率 $M = m_o \times M_e$。
- Refracting telescope折射望远镜 — objective (large $f_o$, collects light) + eyepiece (short $f_e$, magnifies). Angular magnification $M = f_o / f_e$. A larger objective increases light-gathering and resolving power.— 物镜(大 $f_o$,汇集光线)+ 目镜(短 $f_e$,放大)。角放大率 $M = f_o / f_e$。物镜越大,集光能力与分辨率越高。
HS-PS4-5: "technological devices use the principles of wave behaviour and wave interactions with matter to transmit and capture information and energy" — cameras, telescopes, and medical imaging are the named examples.NGSS HS-PS4-5:"技术装置利用波动行为与波和物质相互作用原理传输和捕获信息与能量"——相机、望远镜与医学成像为具体举例。
A refracting telescope has an objective lens of focal length $f_o = 90$ cm and an eyepiece of focal length $f_e = 1.5$ cm. (a) What is the angular magnification? (b) If the objective lens has a diameter of $8.0$ cm, by what factor does it increase the area of light collected compared to the human pupil ($d = 0.8$ cm$)$?一架折射望远镜物镜焦距 $f_o = 90$ cm,目镜焦距 $f_e = 1.5$ cm。(a) 角放大率是多少?(b) 若物镜直径为 $8.0$ cm,与人眼瞳孔($d = 0.8$ cm)相比,集光面积增大多少倍?
(a) Angular magnification.(a) 角放大率。
$$ M = \frac{f_o}{f_e} = \frac{90}{1.5} = 60. $$(b) Light-collecting area ratio.(b) 集光面积之比。 Area scales as diameter squared:面积随直径的平方缩放:
$$ \frac{A_{\text{objective}}}{A_{\text{pupil}}} = \left(\frac{d_o}{d_p}\right)^2 = \left(\frac{8.0}{0.8}\right)^2 = 10^2 = 100. $$Interpret.解读。 The telescope magnifies distant objects $60\times$ in angle and collects $100$ times more light than the naked eye — these two independent improvements explain why even modest telescopes reveal stars invisible to the unaided eye.望远镜使远处物体在角度上放大 $60$ 倍,集光量是裸眼的 $100$ 倍 — 这两项独立的改进解释了为何即使普通望远镜也能看到肉眼不可见的星星。
Going deeper — cameras: the pinhole, the single-lens, and autofocus深入 — 相机:针孔相机、单镜头相机与自动对焦
A pinhole camera works with no lens at all: a tiny hole in one wall of a dark box projects an inverted image of the scene onto the opposite wall. Every point of the scene sends a thin cone of rays through the hole; a smaller hole gives a sharper (but dimmer) image. The image obeys the same geometry as a lens: the image-to-pinhole distance $v$ and the object-to-pinhole distance $u$ satisfy $h_i/h_o = v/u$ for image height $h_i$ and object height $h_o$.针孔相机无需任何透镜:暗箱一侧壁上的小孔将场景的倒立像投射到对侧壁上。场景的每一点通过小孔发射一细锥形光束;孔越小,像越清晰(但越暗)。像遵循与透镜相同的几何关系:像到针孔距离 $v$ 与物到针孔距离 $u$ 满足 $h_i/h_o = v/u$($h_i$ 为像高,$h_o$ 为物高)。
A modern camera replaces the pinhole with a lens (or lens group). Focusing is achieved by moving the lens relative to the sensor, so that the lens equation $1/f = 1/d_o + 1/d_i$ is satisfied for the current object distance. Autofocus systems use a phase-detection sensor or a contrast-detection algorithm to determine the correct $d_i$ and drive the lens motor accordingly. The aperture (f-stop) controls depth of field: a small aperture (large f-number) keeps both near and far objects in focus; a large aperture gives a shallow depth of field and isolates subjects against a blurred background.现代相机用透镜(或透镜组)取代针孔。对焦通过移动透镜相对于传感器的位置来实现,使透镜方程 $1/f = 1/d_o + 1/d_i$ 对当前物距成立。自动对焦系统使用相位检测传感器或对比度检测算法确定正确的 $d_i$,并驱动镜头电机。光圈(f 值)控制景深:小光圈(大 f 值)使近处和远处物体都清晰;大光圈景深浅,使主体从模糊背景中突出。
Exam Strategy and Common Pitfalls考试策略与常见陷阱
- Draw a ray diagram first.先画光路图。 Sketch the geometry before applying any formula. The diagram reveals whether the image is real or virtual and what sign to assign $d_i$. Skipping this step is the single most common source of sign errors in optics problems.套用任何公式前先画出几何图形。图能揭示像是实像还是虚像,以及 $d_i$ 应取什么符号。跳过此步是光学题中符号错误最常见的来源。
- Adopt the real-positive sign convention consistently.始终采用实-为-正的符号约定。 $d_o > 0$ always; $d_i > 0$ for real images (on the far side of a lens or in front of a mirror); $d_i < 0$ for virtual images. Focal length: converging lens or concave mirror $f > 0$; diverging lens or convex mirror $f < 0$.$d_o > 0$ 恒成立;$d_i > 0$ 为实像(透镜远侧或镜前);$d_i < 0$ 为虚像。焦距:会聚透镜或凹镜 $f > 0$;发散透镜或凸镜 $f < 0$。
- Measure all angles from the normal, not the surface.所有角度从法线量起,而非从界面量起。 Both the law of reflection and Snell's law use the angle between the ray and the normal to the surface at the point of incidence. Measuring from the surface instead gives the complement of the correct angle.反射定律和斯涅尔定律均使用光线与入射点处界面法线之间的角度。从界面量会得到正确角度的余角。
- Law of reflection: $\theta_i = \theta_r$ from the normal.反射定律:$\theta_i = \theta_r$,从法线量。 Plane mirrors give virtual, upright, same-size images at the same distance behind the mirror.平面镜产生虚像、正立、等大,像距等于物距(在镜后)。
- Snell's law: $n_1\sin\theta_1 = n_2\sin\theta_2$.斯涅尔定律:$n_1\sin\theta_1 = n_2\sin\theta_2$。 Into a denser medium: bends toward the normal. Into a less dense medium: bends away. If you get $\sin\theta_2 > 1$ in Snell's law, you have a TIR situation.进入光密介质:偏向法线。进入光疏介质:偏离法线。若斯涅尔定律给出 $\sin\theta_2 > 1$,即为全内反射情形。
- TIR critical angle: $\sin\theta_c = n_2/n_1$ (with $n_1 > n_2$).全内反射临界角:$\sin\theta_c = n_2/n_1$($n_1 > n_2$)。 TIR only occurs when light travels from dense to less-dense media and $\theta_1 > \theta_c$.全内反射只在光从光密射向光疏介质且 $\theta_1 > \theta_c$ 时发生。
- The equations are the same form: $\tfrac{1}{f} = \tfrac{1}{d_o} + \tfrac{1}{d_i}$.方程形式相同:$\tfrac{1}{f} = \tfrac{1}{d_o} + \tfrac{1}{d_i}$。 The only difference is the sign convention for where real vs virtual images land relative to the optical element.唯一区别是实像与虚像相对于光学元件位置的符号约定。
- Magnification sign tells you orientation.放大率符号告诉你像的取向。 $m = -d_i/d_o$: negative $m$ means inverted (real image for lenses/concave mirrors); positive $m$ means upright (virtual image).$m = -d_i/d_o$:$m$ 为负表示倒立(透镜/凹镜的实像);$m$ 为正表示正立(虚像)。
- Trace the three principal rays to check the formula result.追踪三条主光线以核验公式结果。 Parallel-to-axis ray, focal-point ray, and centre-of-curvature (or optical-centre for lenses) ray: their intersection locates the image.平行轴光线、焦点光线和曲率中心光线(透镜用光心光线):三线交点即为像的位置。
- State the nature of the image.说明像的性质。 Full marks in Ontario SPH3U and Alberta Physics 30 require you to state: real or virtual, upright or inverted, enlarged/same size/diminished, and the image distance with correct sign and units.安大略 SPH3U 和阿尔伯塔 Physics 30 的满分要求你说明:实像还是虚像、正立还是倒立、放大/等大/缩小,以及带正确符号和单位的像距。
- Round at the very end.最后一步再四舍五入。 Carry extra digits through intermediate steps; round only the final answer to the precision the question requests.中间步骤多留几位;仅在最终答案处按题目要求的精度四舍五入。
- Sanity-check the sign of $d_i$.核验 $d_i$ 的符号。 A positive $d_i$ from the thin-lens equation means a real image; negative means virtual. If your ray diagram and your arithmetic disagree, recheck the sign of $f$.薄透镜方程给出正 $d_i$ 意味实像;负值意味虚像。若光路图与算术结果不符,重新检查 $f$ 的符号。
Flashcards闪卡
Practice Quiz综合测验
Readiness Checklist准备就绪清单
Tick each item when you can do it cold, without notes, on a first attempt.能在无笔记、首次尝试下完成,再勾选每一项。
- State the two models of light (wave and photon) and give one phenomenon better explained by each. 🇺🇸 NGSS HS-PS4-3陈述光的两种模型(波动与光子),并各举一个更适合该模型解释的现象。🇺🇸 NGSS HS-PS4-3
- Order all seven EM spectrum regions from lowest to highest frequency (and highest to lowest wavelength), and relate photon energy to frequency via $E = hf$.将电磁波谱的七个区域按频率从低到高(波长从高到低)排列,并通过 $E = hf$ 将光子能量与频率联系起来。
- Apply the law of reflection ($\theta_i = \theta_r$ from the normal) and list the four properties of a plane-mirror image. 🇨🇦 ON SPH3U / AB 30–C1.6k应用反射定律($\theta_i = \theta_r$,从法线量)并列出平面镜像的四个特性。🇨🇦 ON SPH3U / AB 30–C1.6k
- Use the mirror equation $\tfrac{1}{f} = \tfrac{1}{d_o} + \tfrac{1}{d_i}$ and magnification $m = -d_i/d_o$ to find image position and describe its nature for a concave or convex mirror. 🇨🇦 AB 30–C1.7k用镜方程 $\tfrac{1}{f} = \tfrac{1}{d_o} + \tfrac{1}{d_i}$ 与放大率 $m = -d_i/d_o$ 求凹镜或凸镜的像位置并描述其性质。🇨🇦 AB 30–C1.7k
- Apply Snell's law $n_1\sin\theta_1 = n_2\sin\theta_2$ to find the refracted angle and explain the direction of bending in terms of the refractive index. 🇨🇦 AB 30–C1.6k / BC Physics 11应用斯涅尔定律 $n_1\sin\theta_1 = n_2\sin\theta_2$ 求折射角,并用折射率解释弯折方向。🇨🇦 AB 30–C1.6k / BC Physics 11
- Calculate the critical angle using $\sin\theta_c = n_2/n_1$ and state the two conditions required for total internal reflection. 🇨🇦 AB 30–C1.6k / ON SPH3U用 $\sin\theta_c = n_2/n_1$ 计算临界角,并说明发生全内反射的两个条件。🇨🇦 AB 30–C1.6k / ON SPH3U
- Explain how an optical fibre confines light using TIR, and identify the role of the core-cladding refractive-index difference. 🇺🇸 NGSS HS-PS4-5解释光纤如何利用全内反射限制光传播,并说明芯-包层折射率差的作用。🇺🇸 NGSS HS-PS4-5
- Use the thin-lens equation and magnification formula to find image position and nature for a converging or diverging lens, including the magnifying-glass case ($d_o < f$). 🇨🇦 AB 30–C1.7k / ON SPH3U用薄透镜方程与放大率公式求会聚或发散透镜的像位置与性质,包括放大镜情形($d_o < f$)。🇨🇦 AB 30–C1.7k / ON SPH3U
- Trace the three principal rays for a converging lens (and mirror) to graphically locate the image, and verify the result with the equation.追踪会聚透镜(和镜)的三条主光线以图解方式确定像的位置,并用方程加以验证。
- Identify the lens correction needed for myopia (diverging, $f < 0$) and hyperopia (converging, $f > 0$), and explain why in terms of where the image falls relative to the retina. 🇨🇦 ON SPH3U判断近视(发散透镜,$f < 0$)和远视(会聚透镜,$f > 0$)所需的镜片矫正,并从像相对于视网膜的位置解释原因。🇨🇦 ON SPH3U
- Calculate the angular magnification of a telescope ($M = f_o/f_e$) and the total magnification of a compound microscope ($M = m_o \times M_e$). 🇺🇸 NGSS HS-PS4-5 / ON SPH3U计算望远镜的角放大率($M = f_o/f_e$)与复合显微镜的总放大率($M = m_o \times M_e$)。🇺🇸 NGSS HS-PS4-5 / ON SPH3U
What This Feeds Into本单元的去向
Light and Geometric Optics builds on the wave foundations of Unit 6 (Waves and Sound) and feeds into modern-physics topics in Unit 12 (photoelectric effect, wave-particle duality). The geometric-optics skills here — Snell's law, lens and mirror equations, ray diagrams — are the quantitative foundation that upper-level courses require. Note: there is no dedicated AP Physics optics unit. AP Physics 1 does not test geometric optics; AP Physics 2 (non-calculus) does, but that course is outside the scope of the HS Physics series. IB Physics HL (Topic C: Wave Behaviour) covers optics quantitatively. The links below point at units already in this repo that share the prerequisite wave content.光与几何光学建立在第 6 单元(波与声)的波动基础之上,并进入第 12 单元(现代物理)的光电效应与波粒二象性话题。此处的几何光学技能 — 斯涅尔定律、透镜与镜方程、光路图 — 是高阶课程所需的定量基础。注意:AP Physics 无专项光学单元。AP Physics 1 不考几何光学;AP Physics 2(非微积分)涵盖光学,但该课程超出本 HS Physics 系列范围。IB Physics HL(Topic C:波动行为)定量地涵盖光学。以下链接指向本仓库中已有的、共享波动先修内容的单元。
Within High School Physics.在 HS Physics 内部。
Unit 6 (Waves and Sound) provides the wave vocabulary (wavelength, frequency, wave speed $v = f\lambda$, reflection, refraction as wave phenomena) that underpins §1 and §4 of this guide. Unit 12 (Modern / Nuclear Physics) picks up where wave-particle duality ends in §1: the photoelectric effect, photon energy, and the quantum model of light all trace directly back to the $E = hf$ relation introduced here.第 6 单元(波与声)提供了波动语汇(波长、频率、波速 $v = f\lambda$、反射、折射作为波动现象),是本指南 §1 和 §4 的基础。第 12 单元(现代/核物理)从 §1 的波粒二象性结束处接续:光电效应、光子能量与光的量子模型均直接追溯到此处引入的 $E = hf$ 关系。
No AP optics feeder link — explanation.无 AP 光学衔接链接 — 说明。
AP Physics 1 (algebra-based) does not test geometric optics; the AP Physics 2 course that does is not part of this HS Physics series. There is therefore no AP optics Study Guide in this repo to link to. Students targeting IB Physics HL should look to Topic C (Wave Behaviour) in the IB Physics HL series for the upper-level treatment of optics that extends the content here.AP Physics 1(代数基础)不考几何光学;涵盖此内容的 AP Physics 2 课程不属于本 HS Physics 系列。因此本仓库中没有可链接的 AP 光学学习指南。备考 IB Physics HL 的学生应参考 IB Physics HL 系列中的 Topic C(波动行为),那里对本指南内容进行了高阶拓展处理。