Introduction to Limits and Calculus极限与微积分入门
Calculus is the mathematics of "what happens as we zoom in." A limit describes the value a function approaches as the input slides toward a target; a derivative is the limit of a slope; an integral is a limit of a sum that totals up signed area. This unit is the AP/IB-feeder introduction at MCV4U level: it builds intuition for $\lim_{x \to c} f(x)$ from graphs and tables, walks the four standard algebraic techniques (direct substitution, factor-and-cancel, conjugate, rationalising), introduces one-sided limits and continuity, defines the derivative as $f'(x) = \lim_{h \to 0} (f(x+h)-f(x))/h$, drills the power rule, and closes with antiderivatives and the definite integral as signed area. The full $\epsilon$-$\delta$ definition, IVT/EVT/MVT, Riemann sums, and the formal Fundamental Theorem all live one step downstream in AP Calculus AB and IB Math HL E-cluster , the feeder links at the end of the guide point straight there.微积分(calculus)研究"无限放大时发生什么"。极限(limit)刻画自变量逼近某目标时函数的趋近值;导数(derivative)是斜率的极限;积分(integral)是把带符号面积累加起来的求和极限。本单元是 MCV4U 级别的 AP / IB 衔接入门:先用图像与数表建立 $\lim_{x \to c} f(x)$ 的直观,再走过四种标准代数技巧(直接代入、因式约分、共轭、有理化),引入单侧极限与连续性,定义导数 $f'(x) = \lim_{h \to 0} (f(x+h)-f(x))/h$,反复练习幂法则,最后以反导数与作为带符号面积的定积分收束。完整的 $\epsilon$-$\delta$ 定义、IVT / EVT / MVT、黎曼和、严格的微积分基本定理都属于下游内容,归 AP Calculus AB 与 IB Math HL E 簇 , 指南末尾的衔接链接直接指过去。
How to use this guide如何使用本指南
Calculus content lives in different places in each of the four curricula we map to. The US Common Core does not contain it at all , CCSSM stops at pre-calculus and AP Calculus AB / BC is where American students meet limits and derivatives. Ontario MCV4U (Grade 12, University) puts it at the centre of the course: Strand A is Rate of Change, Strand B is Derivatives. BC and Alberta both offer dedicated optional Grade 12 calculus courses (Calculus 12 and Math 31) that cover this material. The table below tells you which sections are on your syllabus right now and where to keep going. Treat this unit as the AP/IB feeder , the deeper material with $\epsilon$-$\delta$ rigor, IVT/EVT/MVT, full differentiation rules, Riemann sums, and the Fundamental Theorem lives in the AP Calculus and IB Math HL units cross-linked at the end.微积分内容在我们对照的四套大纲中位置各异。美国共同核心完全不含 , CCSSM 止于 pre-calculus,AP Calculus AB / BC 是美国学生接触极限与导数的地方。安大略 MCV4U(12 年级大学预备)把这部分放在课程核心:单元 A 为变化率,单元 B 为导数。BC 与阿尔伯塔都开设 12 年级专属选修微积分课程(Calculus 12、Math 31),覆盖同样内容。下表说明你的大纲下应学哪几节、以及深入路径。把本单元视为 AP / IB 衔接 , 严格的 $\epsilon$-$\delta$ 定义、IVT / EVT / MVT、完整的微分法则、黎曼和与微积分基本定理见末尾的 AP Calculus 与 IB Math HL 链接。
| If you are in…如果你在… | Focus on these sections重点学习 | Defer / skip可推迟 | Source依据 |
|---|---|---|---|
| 🇺🇸 US Grade 11/12 , CCSSM Pre-Calc only美国 11/12 年级 , 仅 CCSSM Pre-Calc | All seven sections as Honors / AP-feeder enrichment. Limits and derivatives are not on the SAT, but they are on the AP Calculus AB exam , this unit is your runway.全部 7 节皆为 Honors / AP 衔接拓展。极限与导数不在 SAT,但在 AP Calculus AB 考试 , 本单元为助跑道。 | Nothing on the unit itself , but if you have not yet seen factoring (HS Math Unit 3) or rational expressions (Unit 4), do those first because §2 lives on them.单元本身无可跳过 , 但若尚未学过因式分解(HS Math Unit 3)或有理表达式(Unit 4),请先补完,因为 §2 依赖它们。 | ccssm_hs_math.pdf , CCSSM HS standards contain no limits / derivatives / integrals. Closest standard: HSF-IF.B.6 (average rate of change). The full pathway is AP Calculus AB CED Units 1, 2, 6., CCSSM 高中标准不含极限 / 导数 / 积分。最接近的标准为 HSF-IF.B.6(平均变化率)。完整路径见 AP Calculus AB CED 的 Unit 1、2、6。 |
| 🇨🇦 ON Grade 12 , MCV4U安大略 12 年级 , MCV4U | §1 through §5 are core. Strand A maps to §1, §2, §3; Strand B maps to §4 and §5. Treat §6 and §7 as enrichment that smooths the transition to first-year university calculus.§1 至 §5 为核心。单元 A 对应 §1、§2、§3;单元 B 对应 §4、§5。§6、§7 为拓展内容,帮助衔接大学一年级微积分。 | §6 and §7 (antiderivatives and definite integrals are not in MCV4U , they live in first-year university calculus or AP Calc AB / BC).§6、§7(反导数与定积分不在 MCV4U , 属大学一年级微积分或 AP Calc AB / BC)。 | math_grades_11-12_extract.md , MCV4U Strand A Rate of Change (limits, average vs instantaneous rate of change) and Strand B Derivatives (power rule, sum and constant multiple rules, derivative graphs). No integral strand., MCV4U 单元 A 变化率(极限、平均变化率与瞬时变化率)与单元 B 导数(幂法则、求和与常数倍法则、导数图像)。无积分单元。 |
| 🇨🇦 BC Grade 12 , Calculus 12 (optional)BC 12 年级 , Calculus 12(选修) | All seven sections. Calculus 12 is BC's pre-university calculus course and covers limits, derivatives, and integrals at the depth of this unit and slightly beyond.全部 7 节。Calculus 12 是 BC 的大学前微积分课程,覆盖极限、导数与积分,深度与本单元一致并稍超出。 | Nothing , treat as the recommended bridge before AP Calc AB or first-year university.无 , 视为 AP Calc AB 或大学一年级前的推荐桥梁。 | calc12.pdf , BC Ministry, Calculus 12. Per-section citations pending until calc12_extract.md is produced., BC 教育厅 Calculus 12。逐节细化引用在 calc12_extract.md 产出前待补。 |
| 🇨🇦 BC Grade 11/12 , PC 11 / PC 12 only (no Calc 12)BC 11/12 年级 , 仅 PC 11 / PC 12 | All seven sections as Honors / AP-feeder enrichment. Pre-Calc 12 contains no calculus content, so this unit is your only pre-AP exposure.全部 7 节作 Honors / AP 衔接拓展。Pre-Calc 12 不含微积分,本单元即为 AP 前唯一接触。 | Nothing , but be honest about timing: if you have not yet finished PC 12 algebra / function chapters, do those first.无 , 但要量力而行:若尚未学完 PC 12 的代数 / 函数章节,请先完成。 | pc12_elab_extract.md , PC 12 content elaborations contain no limits / derivatives / integrals., PC 12 内容细化不含极限 / 导数 / 积分。 |
| 🇨🇦 AB Grade 12 , Math 31 (optional)阿尔伯塔 12 年级 , Math 31(选修) | All seven sections. Math 31 is Alberta's introductory calculus course , same scope as BC Calc 12.全部 7 节。Math 31 是阿尔伯塔的入门微积分课程 , 范围与 BC Calc 12 一致。 | Nothing , use as a clean second pass before AP Calc AB or first-year university calculus.无 , AP Calc AB 或大学一年级微积分之前作为干净复习。 | math31.pdf , Alberta Education, Math 31 Program of Studies. Per-section citations pending until math31_extract.md is produced., 阿尔伯塔教育厅 Math 31 课程大纲。逐节细化引用在 math31_extract.md 产出前待补。 |
| 🇨🇦 AB Grade 11/12 , Math 30-1 only (no Math 31)阿尔伯塔 11/12 年级 , 仅 Math 30-1 | All seven sections as Honors / AP-feeder enrichment. Math 30-1 is pre-calculus , calculus is Math 31 only.全部 7 节作 Honors / AP 衔接拓展。Math 30-1 是 pre-calculus , 微积分仅限 Math 31。 | Nothing on the unit. If you intend to sit AP Calc, study the AP feeders linked at the end too.单元本身无可跳过。若打算考 AP Calc,末尾的 AP 衔接也要看。 | math30-1_standards_exemplars.pdf , Math 30-1 contains no limits / derivatives / integrals., Math 30-1 不含极限 / 导数 / 积分。 |
| 🇺🇸 US AP-feeder (Pre-Calc / Honors)美国 AP 衔接(Pre-Calc / 荣誉) | All seven sections plus the feeder links. AP Calculus AB Unit 1 picks up exactly at §1-§3 with $\epsilon$-$\delta$ added; Unit 2 picks up at §4-§5; Unit 6 picks up at §6-§7 with Riemann sums and the Fundamental Theorem added.全部 7 节加末尾衔接链接。AP Calculus AB Unit 1 自 §1-§3 起接续并加入 $\epsilon$-$\delta$;Unit 2 自 §4-§5 起接续;Unit 6 自 §6-§7 起接续并加入黎曼和与微积分基本定理。 | Nothing , this unit is exactly the right pre-read for AP Calc.无 , 本单元正是 AP Calc 的合适前置阅读。 | AP Calculus AB CED (College Board), Units 1 (Limits and Continuity), 2 (Differentiation: Definition and Fundamental Properties), 6 (Integration and Accumulation of Change).AP Calculus AB CED(College Board)的 Unit 1(极限与连续)、Unit 2(微分:定义与基本性质)、Unit 6(积分与变化量的累积)。 |
Once you have located your row, use the two cards below for the speed at which you should work through the recommended sections.找到所在行后,用下面两张卡片决定推进速度。
Memorise five things: the meaning of $\lim_{x \to c} f(x) = L$ ("$f(x)$ gets arbitrarily close to $L$ as $x$ gets close to $c$"); the factor-and-cancel move for $0/0$ forms; the derivative definition $f'(x) = \lim_{h \to 0} (f(x+h)-f(x))/h$; the power rule $(x^n)' = n x^{n-1}$ and its reverse $\int x^n \, dx = x^{n+1}/(n+1) + C$; the picture of the definite integral as signed area between the graph and the $x$-axis. Read every cram-cheat box. Skip the derivations.背熟五件事:$\lim_{x \to c} f(x) = L$ 的含义("当 $x$ 趋于 $c$ 时 $f(x)$ 任意接近 $L$");$0/0$ 型用因式约分;导数定义 $f'(x) = \lim_{h \to 0} (f(x+h)-f(x))/h$;幂法则 $(x^n)' = n x^{n-1}$ 与其逆 $\int x^n \, dx = x^{n+1}/(n+1) + C$;定积分作为图像与 $x$ 轴间带符号面积的几何图像。读每个速记框,跳过推导。
Always justify a limit. "$\lim_{x \to 2} (x^2 - 4)/(x - 2) = 4$ because after factoring and cancelling we have $\lim_{x \to 2}(x + 2) = 4$" earns the method mark; the bare $4$ does not. Always write the derivative definition before invoking the power rule on a "from first principles" question (MCV4U Strand A expects exactly this). Memorise the antiderivative form with $+ C$ , missing the constant is the single most common AB / BC exam slip. Read the derivation linking the derivative to a secant slope and the derivation that turns the area-under-a-graph picture into $\int_a^b f(x) \, dx$.每个极限都要给出理由。"$\lim_{x \to 2} (x^2 - 4)/(x - 2) = 4$,因为因式约分后 $\lim_{x \to 2}(x + 2) = 4$"能拿到方法分;只写 $4$ 不能。"从定义出发"求导时务必先写导数定义(MCV4U 单元 A 正是此要求)。反导数务必带 $+ C$ , 漏掉常数是 AB / BC 考试最常见的单点失分。两条推导都要会:把割线斜率推为导数;把图像下方面积推为 $\int_a^b f(x) \, dx$。
Intuitive Limits: Graphs and Tables直观的极限:图像与数表
As $x$ gets arbitrarily close to $c$ from either side (but never equal to $c$), the value of $f(x)$ gets arbitrarily close to $L$. The limit does not care what $f(c)$ is , only what $f$ does on a small neighbourhood around $c$.当 $x$ 从两侧任意接近 $c$(但不等于 $c$)时,$f(x)$ 任意接近 $L$。极限不在乎 $f(c)$ 本身的值 , 它只关心 $f$ 在 $c$ 附近邻域上的行为。
- Two ways to read a limit.读极限的两种方式。 Graphical: zoom in on the graph near $x = c$; the $y$-value the curve approaches is the limit. Tabular: tabulate $f(x)$ at $x$-values that creep up on $c$ from both sides; the shared trend value is the limit.图像法:在 $x = c$ 附近放大图像,曲线趋近的 $y$ 值即极限。数表法:列出从两侧逼近 $c$ 的 $x$ 处的 $f(x)$,两侧共同趋近的值即极限。
- "Hole" example."洞"的例子。 For $f(x) = (x^2 - 1)/(x - 1)$, the value $f(1)$ is undefined ($0/0$), but the limit $\lim_{x \to 1} f(x) = 2$ exists because $f(x) = x + 1$ for $x \ne 1$.对 $f(x) = (x^2 - 1)/(x - 1)$,$f(1)$ 未定义($0/0$),但极限 $\lim_{x \to 1} f(x) = 2$ 存在,因为 $x \ne 1$ 时 $f(x) = x + 1$。
- Why this matters.为何重要。 The derivative ($\S 4$) and the definite integral ($\S 7$) are both limits. Without limits, no calculus. MCV4U Strand A spells this out: "make connections between average rate of change over an interval and instantaneous rate of change at a point, using the slopes of secants and tangents and the concept of the limit."导数(§4)与定积分(§7)都是极限。没有极限就没有微积分。MCV4U 单元 A 明确:"通过把区间上的平均变化率与某点的瞬时变化率联系起来,并使用割线、切线斜率与极限概念。"
Let $f(x) = \dfrac{\sin x}{x}$ with $x$ in radians. Estimate $\lim_{x \to 0} f(x)$ by tabulating $f$ at $x = \pm 0.1, \pm 0.01, \pm 0.001$.设 $f(x) = \dfrac{\sin x}{x}$,$x$ 为弧度。在 $x = \pm 0.1, \pm 0.01, \pm 0.001$ 处列表估计 $\lim_{x \to 0} f(x)$。
Why we cannot just plug in.为何不能直接代入。 $f(0) = 0/0$, which is indeterminate , not a value. So we tabulate on both sides instead.$f(0) = 0/0$ 是未定式 , 没有数值。所以从两侧列表逼近。
| $x$ | $-0.1$ | $-0.01$ | $-0.001$ | $+0.001$ | $+0.01$ | $+0.1$ |
|---|---|---|---|---|---|---|
| $f(x)$ | $0.99833$ | $0.99998$ | $1.00000$ | $1.00000$ | $0.99998$ | $0.99833$ |
Both sides agree.两侧吻合。 As $x \to 0$ from either side, $f(x)$ approaches $1$. So:$x$ 从两侧趋于 $0$ 时,$f(x)$ 趋近 $1$。故:
$$ \lim_{x \to 0} \frac{\sin x}{x} \;=\; 1. $$Caveat.注意。 A table is a strong piece of evidence, not a proof. AP Calc and IB Math HL both have algebraic / squeeze-theorem proofs of this exact limit , see the AP Calc Unit 1 feeder.数表是有力证据,但不是证明。AP Calc 与 IB Math HL 都用代数 / 夹挤定理给出此极限的严格证明 , 见 AP Calc Unit 1 衔接。
Computing Limits Algebraically用代数方法计算极限
- Direct substitution.直接代入。 If $f$ is "nice" (polynomial, or rational with non-zero denominator, etc.), then $\lim_{x \to c} f(x) = f(c)$. Always try this first.若 $f$ "好"(多项式,或分母不为零的有理式等),则 $\lim_{x \to c} f(x) = f(c)$。先试此法。
- Factor and cancel因式分解并约分 when substitution gives the indeterminate form $0/0$. Common when the numerator and denominator share a factor $(x - c)$.当代入得未定式 $0/0$ 时。常见于分子分母含公因式 $(x - c)$ 的情形。
- Conjugate technique共轭法 when the expression contains a $\sqrt{\,}$ that creates a $0/0$ form. Multiply numerator and denominator by the conjugate to rationalise.当表达式含 $\sqrt{\,}$ 且产生 $0/0$ 时。分子分母同乘共轭以有理化。
- Rationalise / common denominator通分 / 化为同分母 for expressions like $\lim_{x \to 0} (1/x)(1/(x+1) - 1)$ , combine the fractions, simplify, then substitute.对于 $\lim_{x \to 0} (1/x)(1/(x+1) - 1)$ 等表达式 , 先通分化简,再代入。
Evaluate $\lim_{x \to 2} \dfrac{x^2 - 4}{x - 2}$.求 $\lim_{x \to 2} \dfrac{x^2 - 4}{x - 2}$。
Try direct substitution.先试直接代入。 $f(2) = (4 - 4)/(2 - 2) = 0/0$ , indeterminate. Cannot finish here.$f(2) = (4 - 4)/(2 - 2) = 0/0$ , 未定式,不能就此结束。
Factor the numerator.对分子因式分解。
$$ \frac{x^2 - 4}{x - 2} \;=\; \frac{(x - 2)(x + 2)}{x - 2} \;=\; x + 2 \quad \text{for } x \ne 2. $$Now substitute into the simplified form.在化简形式下代入。
$$ \lim_{x \to 2} \frac{x^2 - 4}{x - 2} \;=\; \lim_{x \to 2} (x + 2) \;=\; 4. $$Why cancelling is legal.约分为何合法。 The limit only looks at $x \ne c$, and on that set the original expression equals $x + 2$ identically. The function has a "hole" at $x = 2$ but the limit is $4$.极限只关注 $x \ne c$,在该集合上原表达式与 $x + 2$ 完全相同。函数在 $x = 2$ 处有"洞",但极限为 $4$。
Evaluate $\lim_{x \to 0} \dfrac{\sqrt{x + 4} - 2}{x}$.求 $\lim_{x \to 0} \dfrac{\sqrt{x + 4} - 2}{x}$。
Direct substitution.直接代入。 $(\sqrt{4} - 2)/0 = 0/0$ , indeterminate.$(\sqrt{4} - 2)/0 = 0/0$ , 未定式。
Multiply by the conjugate.同乘共轭式。
$$ \frac{\sqrt{x + 4} - 2}{x} \cdot \frac{\sqrt{x + 4} + 2}{\sqrt{x + 4} + 2} \;=\; \frac{(x + 4) - 4}{x (\sqrt{x + 4} + 2)} \;=\; \frac{x}{x (\sqrt{x + 4} + 2)}. $$Cancel and substitute.约分并代入。
$$ \;=\; \frac{1}{\sqrt{x + 4} + 2} \;\xrightarrow{x \to 0}\; \frac{1}{\sqrt{4} + 2} \;=\; \frac{1}{4}. $$Sanity-check.合理性核验。 A table at $x = 0.01$ gives $(\sqrt{4.01} - 2)/0.01 \approx 0.2497$, near $0.25 = 1/4$. ✓在 $x = 0.01$ 处数表:$(\sqrt{4.01} - 2)/0.01 \approx 0.2497$,接近 $0.25 = 1/4$ ✓。
One-Sided Limits, Continuity, and Limits at Infinity单侧极限、连续性与无穷处的极限
- One-sided limits.单侧极限。 $\lim_{x \to c^-} f(x)$ means $x$ approaches $c$ from the left (smaller values); $\lim_{x \to c^+} f(x)$ from the right. The two-sided limit $\lim_{x \to c} f(x)$ exists if and only if both one-sided limits exist and are equal.$\lim_{x \to c^-} f(x)$ 表示 $x$ 从左侧(更小值)逼近 $c$;$\lim_{x \to c^+} f(x)$ 从右侧。双侧极限 $\lim_{x \to c} f(x)$ 存在当且仅当两个单侧极限都存在且相等。
- Continuity at a point.在某点的连续性。 $f$ is continuous at $x = c$ when all three conditions hold: (1) $f(c)$ is defined; (2) $\lim_{x \to c} f(x)$ exists; (3) $\lim_{x \to c} f(x) = f(c)$.$f$ 在 $x = c$ 处连续,须三件事同时成立:(1) $f(c)$ 有定义;(2) $\lim_{x \to c} f(x)$ 存在;(3) $\lim_{x \to c} f(x) = f(c)$。
- Limits at infinity无穷处的极限 describe end behaviour: $\lim_{x \to \infty} f(x) = L$ means $f(x)$ approaches $L$ for arbitrarily large $x$. Geometrically, $y = L$ is a horizontal asymptote.描述尾部行为:$\lim_{x \to \infty} f(x) = L$ 表示 $x$ 任意大时 $f(x)$ 趋近 $L$。几何上 $y = L$ 是水平渐近线。
- Rational-function trick.有理函数技巧。 For $f(x) = (a_n x^n + \ldots)/(b_m x^m + \ldots)$ as $x \to \infty$: if $n < m$ the limit is $0$; if $n = m$ it is $a_n / b_m$; if $n > m$ it is $\pm \infty$.$x \to \infty$ 时对有理函数 $f(x) = (a_n x^n + \ldots)/(b_m x^m + \ldots)$:若 $n < m$ 极限为 $0$;若 $n = m$ 为 $a_n / b_m$;若 $n > m$ 为 $\pm \infty$。
Let $f(x) = \begin{cases} x + 1 & x < 2 \\ x^2 & x \ge 2 \end{cases}$. Determine $\lim_{x \to 2^-} f(x)$, $\lim_{x \to 2^+} f(x)$, $\lim_{x \to 2} f(x)$, and decide whether $f$ is continuous at $x = 2$.设 $f(x) = \begin{cases} x + 1 & x < 2 \\ x^2 & x \ge 2 \end{cases}$。求 $\lim_{x \to 2^-} f(x)$、$\lim_{x \to 2^+} f(x)$、$\lim_{x \to 2} f(x)$,并判断 $f$ 在 $x = 2$ 处是否连续。
Left-side limit.左侧极限。 $\lim_{x \to 2^-} f(x) = \lim_{x \to 2^-} (x + 1) = 3$.$\lim_{x \to 2^-} f(x) = \lim_{x \to 2^-} (x + 1) = 3$。
Right-side limit.右侧极限。 $\lim_{x \to 2^+} f(x) = \lim_{x \to 2^+} x^2 = 4$.$\lim_{x \to 2^+} f(x) = \lim_{x \to 2^+} x^2 = 4$。
Two-sided limit.双侧极限。 Because $3 \ne 4$, $\lim_{x \to 2} f(x)$ does not exist. The graph has a jump of size $1$ at $x = 2$.因为 $3 \ne 4$,所以 $\lim_{x \to 2} f(x)$ 不存在。图像在 $x = 2$ 处有大小 $1$ 的跳跃。
Continuity.连续性。 Condition (2) of the three-part test fails, so $f$ is not continuous at $x = 2$. (It is continuous at every other real number.)三条件测试的第 (2) 条不成立,故 $f$ 在 $x = 2$ 不连续。(在其他实数处皆连续。)
Find $\lim_{x \to \infty} \dfrac{3x^2 + x - 5}{2x^2 + 7}$.求 $\lim_{x \to \infty} \dfrac{3x^2 + x - 5}{2x^2 + 7}$。
Divide numerator and denominator by the highest power of $x$.分子分母同除以 $x$ 的最高次幂。 Here that is $x^2$.此处即 $x^2$。
$$ \frac{3x^2 + x - 5}{2x^2 + 7} \;=\; \frac{3 + 1/x - 5/x^2}{2 + 7/x^2}. $$Take the limit term by term.逐项求极限。 As $x \to \infty$, $1/x \to 0$ and $1/x^2 \to 0$.$x \to \infty$ 时 $1/x \to 0$,$1/x^2 \to 0$。
$$ \;\to\; \frac{3 + 0 - 0}{2 + 0} \;=\; \frac{3}{2}. $$Geometric reading.几何解读。 The horizontal line $y = 3/2$ is a horizontal asymptote of the curve. Matches the cram-cheat shortcut: same degree, ratio of leading coefficients $= 3/2$.水平线 $y = 3/2$ 是曲线的水平渐近线。与速记一致:同次时取首项系数之比 $= 3/2$。
The Derivative as a Limit of a Slope作为斜率极限的导数
Pick a point $(x, f(x))$ and a nearby point $(x + h, f(x + h))$ on the graph. The line through them is the secant; its slope is the average rate of change:在图像上取一点 $(x, f(x))$ 与邻近点 $(x + h, f(x + h))$。两点连线为割线,其斜率即平均变化率:
$$ \frac{f(x + h) - f(x)}{h}. $$As $h \to 0$, the secant rotates and limits onto the tangent line at $x$. The slope of that tangent is the derivative:当 $h \to 0$ 时,割线旋转并以 $x$ 处的切线为极限。该切线斜率即导数:
$$ f'(x) \;=\; \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}. $$- Notation.记号。 $f'(x)$, $\dfrac{df}{dx}$, $\dfrac{dy}{dx}$, $Df(x)$ , all mean the same thing.$f'(x)$、$\dfrac{df}{dx}$、$\dfrac{dy}{dx}$、$Df(x)$ , 含义相同。
- Geometric meaning.几何意义。 $f'(c)$ is the slope of the tangent line to $y = f(x)$ at $x = c$. Positive: curve rising. Negative: falling. Zero: horizontal tangent (often a max / min).$f'(c)$ 是 $y = f(x)$ 在 $x = c$ 处切线的斜率。正:曲线上升;负:下降;零:水平切线(常对应极值)。
- "From first principles""从定义出发" means using this limit directly. MCV4U Strand A and AP Calc Unit 2 both require students to compute at least one derivative this way before reaching for shortcut rules.指直接用此极限求导。MCV4U 单元 A 与 AP Calc Unit 2 都要求至少有一次"从定义出发"求导,才能套用法则。
Let $f(x) = x^2$. Use the limit definition to find $f'(x)$.设 $f(x) = x^2$。用极限定义求 $f'(x)$。
Write the difference quotient.写出差商。
$$ \frac{f(x + h) - f(x)}{h} \;=\; \frac{(x + h)^2 - x^2}{h}. $$Expand and simplify.展开并化简。
$$ \;=\; \frac{x^2 + 2 x h + h^2 - x^2}{h} \;=\; \frac{2 x h + h^2}{h} \;=\; 2 x + h \quad \text{for } h \ne 0. $$Take the limit.取极限。
$$ f'(x) \;=\; \lim_{h \to 0} (2 x + h) \;=\; 2 x. $$Geometric interpretation.几何解读。 At $x = 1$, $f'(1) = 2$ , the parabola $y = x^2$ has tangent slope $2$ at $(1, 1)$. At $x = 0$, $f'(0) = 0$ , horizontal tangent at the vertex. Matches the picture.$x = 1$ 时 $f'(1) = 2$ , 抛物线 $y = x^2$ 在 $(1, 1)$ 处切线斜率为 $2$。$x = 0$ 时 $f'(0) = 0$ , 顶点处水平切线,与图一致。
The Power Rule and Linearity幂法则与线性性
- Power rule.幂法则。 Bring the exponent down as a coefficient, subtract one from the exponent. Works for every real $n$ (MCV4U verifies it for natural $n$; the AP Calc / IB feeders prove the general case).把指数变为系数,指数减一。对任意实数 $n$ 都成立(MCV4U 仅对自然数 $n$ 验证;AP Calc / IB 衔接证明一般情形)。
- Constant multiple.常数倍法则。 Multiplying $f$ by a constant multiplies its derivative by the same constant. Constants pass through differentiation untouched.$f$ 乘常数后,导数也乘以同一常数。常数对求导是"透明"的。
- Sum / difference rule.求和 / 差法则。 Differentiate term by term. Powerful in combination with the power rule for any polynomial.逐项求导。与幂法则结合可对任意多项式求导。
- Derivative of a constant is zero.常数的导数为零。 $\dfrac{d}{dx}[k] = 0$. Geometrically, a horizontal line has slope zero everywhere.$\dfrac{d}{dx}[k] = 0$。几何上水平直线处处斜率为零。
Differentiate $f(x) = 5 x^4 - 3 x^2 + 7 x - 8$.对 $f(x) = 5 x^4 - 3 x^2 + 7 x - 8$ 求导。
Differentiate each term.逐项求导。
$$ \frac{d}{dx}[5 x^4] = 5 \cdot 4 x^3 = 20 x^3. $$ $$ \frac{d}{dx}[-3 x^2] = -3 \cdot 2 x = -6 x. $$ $$ \frac{d}{dx}[7 x] = 7. $$ $$ \frac{d}{dx}[-8] = 0. $$Combine.合并。
$$ f'(x) \;=\; 20 x^3 - 6 x + 7. $$Evaluate at a point.在某点取值。 For example $f'(1) = 20 - 6 + 7 = 21$ , the tangent to $y = f(x)$ at $x = 1$ has slope $21$.如 $f'(1) = 20 - 6 + 7 = 21$ , $y = f(x)$ 在 $x = 1$ 处切线斜率为 $21$。
Differentiate $g(x) = \dfrac{1}{x^2} + \sqrt{x}$ by rewriting with exponents.将 $g(x) = \dfrac{1}{x^2} + \sqrt{x}$ 改写为指数形式后求导。
Rewrite.改写。
$$ g(x) \;=\; x^{-2} + x^{1/2}. $$Apply the power rule term by term.逐项套用幂法则。
$$ g'(x) \;=\; -2 x^{-3} + \tfrac{1}{2} x^{-1/2}. $$Re-express in clean form.化为整洁形式。
$$ g'(x) \;=\; -\frac{2}{x^3} + \frac{1}{2 \sqrt{x}}. $$Sanity-check.合理性核验。 $1/x^2$ decreases as $x$ grows, so its derivative should be negative for $x > 0$ , matches the $-2/x^3$ term.$x > 0$ 时 $1/x^2$ 随 $x$ 增大而减小,其导数应为负 , 与 $-2/x^3$ 一致。
Antiderivatives and the Indefinite Integral Honors — US (AP Calc feeder)反导数与不定积分 荣誉 — US(AP Calc 衔接)
An antiderivative of $f(x)$ is any function $F(x)$ with $F'(x) = f(x)$. Antiderivatives are unique only up to an additive constant: if $F'(x) = f(x)$, then $(F + C)'(x) = f(x)$ too. The notation $\int f(x) \, dx$ stands for the entire family.$f(x)$ 的反导数是任何满足 $F'(x) = f(x)$ 的函数 $F(x)$。反导数仅在差一常数的意义下唯一:若 $F'(x) = f(x)$,则 $(F + C)'(x) = f(x)$ 也成立。记号 $\int f(x) \, dx$ 表示整族。
$$ \int x^n \, dx \;=\; \frac{x^{n + 1}}{n + 1} + C \quad \text{for } n \ne -1. $$- Reverse the power rule.幂法则倒过来。 Add one to the exponent, divide by the new exponent. Then add $+ C$.指数加一,除以新指数,再加 $+ C$。
- Why $n \ne -1$.为何 $n \ne -1$。 If $n = -1$, the formula gives $x^0 / 0$ , undefined. The antiderivative of $1/x$ is $\ln |x| + C$, an exception that AP Calc Unit 6 and IB Math HL E3 treat carefully.若 $n = -1$,公式给出 $x^0 / 0$ , 未定义。$1/x$ 的反导数是 $\ln |x| + C$,AP Calc Unit 6 与 IB Math HL E3 专门处理此例外。
- Linearity carries over.线性性同样保留。 $\int (c \cdot f) \, dx = c \int f \, dx$ and $\int (f \pm g) \, dx = \int f \, dx \pm \int g \, dx$.$\int (c \cdot f) \, dx = c \int f \, dx$;$\int (f \pm g) \, dx = \int f \, dx \pm \int g \, dx$。
- Never forget $+ C$.永远别漏 $+ C$。 An indefinite integral without the constant is wrong by a whole infinite family of functions. AP Calc / IB markers deduct for this.不带常数的不定积分错了整整一族函数。AP Calc / IB 评卷会扣分。
Find $\int (6 x^2 - 4 x + 5) \, dx$.求 $\int (6 x^2 - 4 x + 5) \, dx$。
Integrate term by term using the power rule in reverse.逐项用幂法则的逆运算积分。
$$ \int 6 x^2 \, dx = 6 \cdot \frac{x^3}{3} = 2 x^3. $$ $$ \int -4 x \, dx = -4 \cdot \frac{x^2}{2} = -2 x^2. $$ $$ \int 5 \, dx = 5 x. $$Combine and add the constant.合并并加上常数。
$$ \int (6 x^2 - 4 x + 5) \, dx \;=\; 2 x^3 - 2 x^2 + 5 x + C. $$Check by differentiating.求导验证。 $\dfrac{d}{dx}[2 x^3 - 2 x^2 + 5 x + C] = 6 x^2 - 4 x + 5$ ✓.$\dfrac{d}{dx}[2 x^3 - 2 x^2 + 5 x + C] = 6 x^2 - 4 x + 5$ ✓。
The Definite Integral as Signed Area Honors — US (AP Calc feeder)作为带符号面积的定积分 荣誉 — US(AP Calc 衔接)
"Signed" means areas above the $x$-axis count positive; areas below count negative. The notation comes from "summing infinitesimal slices": $\int$ is a stretched-out $S$ for "sum," and $dx$ is the width of each slice."带符号"指 $x$ 轴上方的面积为正,下方为负。记号源自"无穷小切片求和":$\int$ 是拉长的 $S$("sum"),$dx$ 是每片的宽度。
- Fundamental Theorem of Calculus (intuitive form).微积分基本定理(直观形式)。 If $F$ is any antiderivative of $f$, then若 $F$ 是 $f$ 的任一反导数,则 $$\int_a^b f(x) \, dx \;=\; F(b) - F(a).$$ In words: definite integration and antidifferentiation are inverse operations. This is the theorem of all of calculus.即:定积分与反导数互为逆运算。这是整个微积分的核心定理。
- No constant on the definite integral.定积分不带常数。 The $+ C$ cancels because $F(b) + C - (F(a) + C) = F(b) - F(a)$. Indefinite integrals carry $+ C$; definite integrals do not.$+ C$ 在差中消去:$F(b) + C - (F(a) + C) = F(b) - F(a)$。不定积分带 $+ C$,定积分不带。
- Reversal sign-flip.交换上下限变号。 $\int_a^b f \, dx = -\int_b^a f \, dx$. Swapping the bounds flips the sign.$\int_a^b f \, dx = -\int_b^a f \, dx$。交换上下限改变符号。
Compute $\int_0^3 x^2 \, dx$ and interpret the result as area.计算 $\int_0^3 x^2 \, dx$ 并将结果解读为面积。
Find an antiderivative.求一个反导数。 By the reverse power rule, $F(x) = x^3 / 3$.由幂法则倒过来,$F(x) = x^3 / 3$。
Apply the Fundamental Theorem.套用微积分基本定理。
$$ \int_0^3 x^2 \, dx \;=\; F(3) - F(0) \;=\; \frac{27}{3} - \frac{0}{3} \;=\; 9. $$Geometric reading.几何解读。 The region bounded by $y = x^2$, the $x$-axis, and the vertical lines $x = 0$ and $x = 3$ has area $9$ square units. Sanity-check: it sits inside a $3 \times 9$ rectangle (area $27$), and $9 = 27/3$ , a third of the rectangle, matching what the picture looks like.由 $y = x^2$、$x$ 轴及竖直线 $x = 0$、$x = 3$ 围成的区域面积为 $9$ 平方单位。验证:它在 $3 \times 9$ 矩形(面积 $27$)内,且 $9 = 27/3$ , 恰为矩形的三分之一,与图一致。
Exam Strategy and Common Pitfalls考试策略与常见陷阱
- Always try substitution first.先试直接代入。 It works for almost every limit at a point of continuity. Only if you get $0/0$ should you reach for factoring or the conjugate.在连续点处几乎总成立。只有得到 $0/0$ 时才用因式分解或共轭。
- $0/0$ does not mean "does not exist."$0/0$ 不等于"不存在"。 It means "do more work." Almost every §2 problem has a clean answer once you factor.它的意思是"还要继续做"。§2 几乎每道题在因式分解后都有干净答案。
- Show the limit symbol through the cancellation.约分过程中保留极限符号。 Write $\lim_{x \to c}$ on every line until the moment you substitute. AP / MCV4U markers want the method, not just the number.在最终代入前,每一行都写 $\lim_{x \to c}$。AP / MCV4U 评卷重视方法过程,不只看数值。
- "From first principles" means write the limit."从定义出发"意味着写出极限。 If the question says "from the definition" or "using the limit," start with $\lim_{h \to 0} (f(x + h) - f(x))/h$. Using the power rule directly will lose method marks.题目若要求"由定义"或"用极限",须从 $\lim_{h \to 0} (f(x + h) - f(x))/h$ 起步。直接套幂法则会丢方法分。
- Constants disappear, exponents drop.常数消失,指数下降。 $(c)' = 0$ and $(x^n)' = n x^{n - 1}$. The most common slip on Q1-style problems is leaving a constant term untouched.$(c)' = 0$、$(x^n)' = n x^{n - 1}$。Q1 型题最常见错误是没动常数项。
- Rewrite radicals and reciprocals as powers先把根式与倒数化为指数 before differentiating. $\sqrt{x} = x^{1/2}$, $1/x = x^{-1}$, $1/x^3 = x^{-3}$. The power rule then handles them mechanically.再求导。$\sqrt{x} = x^{1/2}$,$1/x = x^{-1}$,$1/x^3 = x^{-3}$。幂法则即可机械处理。
- Never forget $+ C$ on indefinite integrals.不定积分务必带 $+ C$。 AP Calc explicitly deducts for missing constants. Indefinite has it; definite does not.AP Calc 对漏常数会扣分。不定积分带,定积分不带。
- Reverse the power rule, then differentiate to check.幂法则倒过来后求导回检。 If $F'(x) = f(x)$, you're correct. This catches both arithmetic slips and the missing-$C$ trap (the $+ C$ check forces you to write it).若 $F'(x) = f(x)$ 即正确。此法同时抓住算术错误与漏常数(写下验证必带 $+ C$)。
- Definite integrals can be negative.定积分可为负。 Area below the $x$-axis counts negative. Read the bounds and the sign of $f$ before you panic about a negative number.$x$ 轴下方面积为负。在为负数惊慌前,先看上下限和 $f$ 的符号。
- $\epsilon$-$\delta$, IVT, EVT, MVT$\epsilon$-$\delta$、IVT、EVT、MVT are AP Calc Unit 1 content. Don't try them here , this unit is the geometric / tabular intuition that makes the formal version click.属 AP Calc Unit 1 内容。本单元不展开 , 这里是几何 / 数表直观,为后续严格化打底。
- Product, quotient, chain rules; $\sin x$, $\cos x$, $e^x$, $\ln x$ derivatives积 / 商 / 链式法则;$\sin x$、$\cos x$、$e^x$、$\ln x$ 的导数 are AP Calc Unit 2 and IB Math HL E2. Bookmark the feeder links once you've nailed the power rule here.属 AP Calc Unit 2 与 IB Math HL E2。掌握幂法则后收藏末尾衔接链接。
- Riemann sums and the formal Fundamental Theorem黎曼和与严格的微积分基本定理 are AP Calc Unit 6 and IB Math HL E3. This unit's signed-area picture is exactly the bridge between the intuitive "limit of a sum" idea and the formal Riemann construction.属 AP Calc Unit 6 与 IB Math HL E3。本单元的带符号面积图正是从"求和的极限"直观到严格黎曼构造的桥梁。
Flashcards闪卡
Practice Quiz综合测验
Readiness Checklist准备就绪清单
Tick each item when you can do it cold, without notes, on a first attempt.能在无笔记、首次尝试下完成,再勾选每一项。
- State in words what $\lim_{x \to c} f(x) = L$ means without referring to $f(c)$, and read a limit off both a graph and a numerical table.用语言陈述 $\lim_{x \to c} f(x) = L$ 的含义而不涉及 $f(c)$,并能从图像与数表读出极限。
- Compute limits algebraically using direct substitution, factor-and-cancel, conjugate, and common-denominator techniques; recognise $0/0$ as an indeterminate prompt for more work.用直接代入、因式约分、共轭、通分四种代数技巧求极限;将 $0/0$ 识别为"还要继续做"的未定式提示。
- Distinguish one-sided limits $\lim_{x \to c^-}$ and $\lim_{x \to c^+}$, and state the existence criterion for the two-sided limit.区分单侧极限 $\lim_{x \to c^-}$ 与 $\lim_{x \to c^+}$,并陈述双侧极限存在的条件。
- State the three-part definition of continuity at a point and use it to classify a discontinuity (removable, jump, infinite).陈述某点连续性的三条件定义,并用它把间断点分类(可去、跳跃、无穷)。
- Find limits at $\pm \infty$ for rational functions by comparing degrees of numerator and denominator; identify horizontal asymptotes.通过比较分子分母次数求有理函数在 $\pm \infty$ 处的极限;识别水平渐近线。
- State the limit definition $f'(x) = \lim_{h \to 0} (f(x + h) - f(x))/h$ and explain why it equals the slope of the tangent line. 🇨🇦 MCV4U Strand A陈述极限定义 $f'(x) = \lim_{h \to 0} (f(x + h) - f(x))/h$ 并说明它为何等于切线斜率。🇨🇦 MCV4U 单元 A
- Compute the derivative of a polynomial (e.g. $f(x) = x^2$, $f(x) = x^3$) from first principles, showing the algebra of the difference quotient.从定义出发求多项式(如 $f(x) = x^2$、$f(x) = x^3$)的导数,展示差商的代数化简过程。
- Apply the power rule $(x^n)' = n x^{n - 1}$, the constant multiple rule, and the sum / difference rule to differentiate any polynomial or rational expression rewritten with exponents. 🇨🇦 MCV4U Strand B运用幂法则 $(x^n)' = n x^{n - 1}$、常数倍法则、求和 / 差法则,对任何多项式或改写为指数形式的有理表达式求导。🇨🇦 MCV4U 单元 B
- Find horizontal-tangent $x$-values by solving $f'(x) = 0$; sketch the curve and the tangent at a given point.求 $f'(x) = 0$ 得到水平切线的 $x$ 值;作出曲线及给定点处的切线。
- Beyond MCV4U State the reverse power rule $\int x^n \, dx = x^{n + 1}/(n + 1) + C$ ($n \ne -1$) and compute indefinite integrals of polynomials.MCV4U 之后陈述幂法则的逆 $\int x^n \, dx = x^{n + 1}/(n + 1) + C$($n \ne -1$),并求多项式的不定积分。
- Beyond MCV4U Interpret $\int_a^b f(x) \, dx$ as signed area between $y = f(x)$ and the $x$-axis, and explain why areas below the axis contribute negatively.MCV4U 之后将 $\int_a^b f(x) \, dx$ 解读为 $y = f(x)$ 与 $x$ 轴间的带符号面积,并解释 $x$ 轴下方区域为何贡献负值。
- Beyond MCV4U Apply the (intuitive) Fundamental Theorem $\int_a^b f \, dx = F(b) - F(a)$ to compute definite integrals of polynomials, and verify with a direct geometric check whenever possible.MCV4U 之后套用(直观形式的)微积分基本定理 $\int_a^b f \, dx = F(b) - F(a)$ 计算多项式的定积分,并在可能时用几何方法直接验证。
What This Feeds Into本单元的去向
This is the feeder unit. Everything you met here is treated formally and at greater depth in the AP Calculus and IB Math HL E-cluster units already shipped in this repo. AP Calculus Unit 1 picks up at §1-§3 with the $\epsilon$-$\delta$ definition, IVT/EVT/MVT, and continuity on closed intervals. AP Calculus Unit 2 picks up at §4-§5 with product, quotient, and chain rules, plus derivatives of $\sin x$, $\cos x$, $e^x$, $\ln x$. AP Calculus Unit 6 picks up at §6-§7 with Riemann sums, the formal Fundamental Theorem, and accumulation functions. The IB Math HL E-cluster covers the same span (E1 principles, E2 techniques, E3 integral techniques, E4 problem-solving, E5 ODEs, E6 Maclaurin) at HL depth.本单元是衔接单元。这里遇到的一切,在仓库已有的 AP Calculus 与 IB Math HL E 簇单元中都会得到严格、更深的处理。AP Calculus Unit 1 自 §1-§3 起接续,加入 $\epsilon$-$\delta$ 定义、IVT / EVT / MVT 与闭区间上的连续性。AP Calculus Unit 2 自 §4-§5 起接续,加入积 / 商 / 链式法则及 $\sin x$、$\cos x$、$e^x$、$\ln x$ 的导数。AP Calculus Unit 6 自 §6-§7 起接续,加入黎曼和、严格的微积分基本定理与累积函数。IB Math HL E 簇覆盖同等内容(E1 原理、E2 技巧、E3 积分技巧、E4 问题求解、E5 常微、E6 麦克劳林),但深度为 HL 级。
Within High School Math.在 HS Math 内部。
This unit is the last HS Math title in the sprint , it sits after Units 1-14 (linear, quadratic, polynomial, rational, exponential / log, sequences, right-triangle trig, unit-circle trig, trig identities, function transformations, combinatorics, probability, statistics, vectors). It draws on Unit 3 (polynomial factoring) and Unit 4 (rational and radical expressions) for the algebraic limit techniques in §2, and on Unit 9's identities for the limit $\lim_{x \to 0} \sin x / x$ touched on in §1.本单元是本冲刺的最后一个 HS Math 标题 , 排在 Unit 1-14 之后(线性、二次、多项式、有理与根式、指数 / 对数、数列、直角三角形三角学、单位圆三角学、三角恒等式、函数变换、排列组合、概率、统计、向量)。§2 的代数限技巧用到 Unit 3(多项式因式分解)与 Unit 4(有理与根式表达式);§1 中触及的 $\lim_{x \to 0} \sin x / x$ 用到 Unit 9 的恒等式。
Across the AP and IB feeders in this repo.本仓库中的 AP 与 IB 衔接单元。
If you are aiming for AP Calculus AB: this unit covers the spine of Units 1, 2, and 6 of the AP CED at intuitive depth , treat the AP feeders as the rigorous second pass before exam season. If you are aiming for IB Math HL: this unit is the prerequisite to the E-cluster (E1-E6); E1 begins exactly where §4 leaves off. If you are aiming for first-year university calculus: this unit plus Calculus 12 / Math 31 (BC / AB) or any AP feeder is the standard runway.备考 AP Calculus AB:本单元在直观深度上覆盖 AP CED 的 Unit 1、Unit 2、Unit 6 主干 , 考试季前用 AP 衔接作严格的第二遍学习。备考 IB Math HL:本单元是 E 簇(E1-E6)的前置;E1 正自 §4 处接续。备考大学一年级微积分:本单元加上 Calculus 12 / Math 31(BC / AB)或任一 AP 衔接,即为标准助跑道。